3x^2-63x=-60

Solution for 3x^2-63x=-60 equation:

3x^2-63x=-60

We move all terms to the left:

3x^2-63x-(-60)=0

We add all the numbers together, and all the variables

3x^2-63x+60=0

a = 3; b = -63; c = +60;
Δ = b2-4ac
Δ = -632-4·3·60
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-57}{2*3}=\frac{6}{6}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+57}{2*3}=\frac{120}{6}
=20
$